Question

In given figure $PQRS$ is a parallelogram. $PM$ is the height from $P$ to $\overline{SR}$ and $PN$ is the height from $P$ to $\overline{QR}$. If $SR=12cm$ and $PM=7.6cm$.
(i) Find the area of the parallelogram $PQRS$
(ii) Find $PN$, if $QR=8cm$.

• A. (i) $91.2c{m}^2$ (ii) $11.4cm$.
• B. (i) $1.2c{m}^2$ (ii) $11.4cm$.
• C. (i) $91.2c{m}^2$ (ii) $1.4cm$.
• D. None of these

Answer 1

Answer: (A)

(i) $91.2c{m}^2$ (ii) $11.4cm$.

$\left(i\right)$ Given: $SR=12cm,PM=7.6cm$

$\therefore$ Area of parallelogram $=SR\times PM=12\times 7.6=91.2c{m}^2$

$\left(ii\right)$ Given: $QR=8cm$ , Area of parallelogram $=91.2c{m}^2$

We know, Area of parallelogram $=QR\times PN$

$\Rightarrow 91.2=8\times PN$

$\Rightarrow PN=\frac{91.2}{8}$

$\Rightarrow PN=11.4cm$

Hence, $\text{A}$ is the correct opton.