Question

In given figure, the minimum distance to reach from point "C" to point "A" will be ....................

• A. $a^2$
• B. $\sqrt{2}$
• C. 2
• D. 2a

Answer 1

The correct option is D 2a

$tanA=\frac{BC}{AB}$

$tan{60}^o=\frac{BC}{a}$

$BC=atan{60}^o$

$BC=\sqrt{3}a$

In $\Delta ABC$,

Using Pythagoras theorem we get,

$A{C}^2=A{B}^2+B{C}^2$

$A{C}^2=a^2+(\sqrt{3}a{)}^2$

$A{C}^2=4a^2$

$AC=2a$