In given figure $△$ ABC and $△$ DEF are similar, BC=3cm, EF=4cm, and area of triangle ABC=54 $c m^{2}$ . Find the area of $△$ DEF. (Note: The given figures are not to scale.)

__ $c m^{2}$

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Solution

We know that the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.

So, $\frac{9}{16} = \frac{54}{a r e a o f △ D E F}$

area of $△ D E F = 96 c m^{2}$

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In given figure $△$ ABC and $△$ DEF are similar, BC = 3cm, EF = 4cm, and area of triangle ABC = 54 $c m^{2}$ find the area of $△$ DEF .

In the given figure, $△ A B C$ and $△ D E F$ are similar. BC = 3 cm, EF = 2 cm, and area of $△ A B C = 54 c m^{2}$ , then the area of $△ D E F$ is __ $c m^{2} .$

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In given figure △ ABC and △ DEF are similar, BC=3cm, EF=4cm, and area of triangle ABC=54cm2. Find the area of △ DEF. (Note: The given figures are not to scale.) __ cm2

We know that the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides. So, 916=54area of △DEF area of △DEF=96cm2

In given figure $△$ ABC and $△$ DEF are similar, BC=3cm, EF=4cm, and area of triangle ABC=54 $c m^{2}$ . Find the area of $△$ DEF. (Note: The given figures are not to scale.)

__ $c m^{2}$

We know that the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.

So, $\frac{9}{16} = \frac{54}{a r e a o f △ D E F}$

area of $△ D E F = 96 c m^{2}$