Question

In going from $O_2$ to $O_2^{+}$, the bond dissociation energy increases and bond length decreases. Do we expect the same behavior for the change $N_2$ and $N_2^{+}$?

Answer 1

It can be explained on the concept of bond order.

In $O_2$ bond order is $2$.

In $O_2^{+}$, bond order $=\frac{(No.ofelectronsinbondingorbital)-(No.ofelectronsinanti-bonding)}{2}$

In $O_2^{+}$, bond order $=\frac{10-5}{5}=2.5$.

$O_2^{+}$ has more bond order than $O_2$. If bond order increases, bond dissosiation energy increases and bond length decreases.

In $N_2$ bond order is $3$.

In $N_2^{+}$, bond order is $\frac{9-4}{2}=2.5$ .

Bond order decreases from ${}^{\prime }{3}^{\prime }$ to $2.5$. $N_2^{+}$ has different behavior and not same with $O_2^{+}$. From $N_2$ to $N_2^{+}$, bond dissosiation energy decreases and bond length increases.