In H2−O2 fuel cell the reaction occuring at cathode is:
A
2H2O+O2+4e−→4OH−
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B
2H2+O2→2H2O(l)
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C
H++OH−→H2O
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D
H++e−→12H2
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Solution
The correct option is A2H2O+O2+4e−→4OH− In H2−O2 fuel cell, hydrogen is oxidised at the anode and oxygen is reduced at the cathode. The half cell reactions are At anode: 2OH−+H2→2H2O+2e− At cathode : 2H2O+O2+4e−→4OH−