Question

In $H_{3}C-C_{1}H=C_2=CH-{CH}_3$, the hybridisation of $C_1$ and $C_2$ are:

• A. $C_1\to sp{C}_2\to sp$
• B. $C_1\to s{p}^2{C}_2\to sp$
• C. $C_1\to s{p}^2{C}_2\to s{p}^2$
• D. $C_1\to s{p}^3{C}_2\to s{p}^2$

Answer 1

The correct option is B $C_1\to s{p}^2{C}_2\to sp$

For carbon there are simple rules for hybridization:

i) $s{p}^2$ if carbon atom has one double bond (alkenes, ketones, etc)

ii) $sp$ if carbon atom has one triple bond or two double bonds (alkynes, alkadienes).

As per the above, we can say

Hybridisation of carbon atoms $C_1$ and $C_2$ in $H_{3}C-C_{1}H=C_2=CH-C{H}_3$ are $s{p}^2$ and $sp$.

$\therefore$ Option B is correct.