Question

In Haber process 30 litres of dihydrogen and 30 litres of dinitrogen were taken for reaction which yielded only 50% of the expected product. What will be the composition of gaseous mixture under the above said conditions in the end?

• A. 10 litres of ammonia, 25 litres nitrogen, 15 litres hydrogen
• B. 20 litres ammonia, 10 litres nitrogen, 30 litres hydrogen
• C. 20 litres ammonia, 25 litres nitrogen, 15 litres hydrogen
• D. 20 litres litres ammonia, 20 litres nitrogen, 20litres hydrogen

Answer 1

Answer: (A)

10 litres of ammonia, 25 litres nitrogen, 15 litres hydrogen

$\begin{array}{ccccc}{N}_2& +& 3H_2& ⟺& 2N{H}_3\\ 30& & 30& & 0\\ 30-x& & 30-3x& & 2x\end{array}$

But $2x=50\%$ of the expected (20 Lt) product = $10lit$

$x=5$

$\therefore$ Vol. of $N_2$ at $eq=30-5=25lit$

$\therefore$ Vol. of $H_2$ at $eq=30-3\times 5=15lit$

$\therefore$ Volume of $N{H}_3$ at equilibrium $=2\times 5=10lit$