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Byju's Answer
Standard XII
Physics
Equipartition Theorem
In Haber's pr...
Question
In Haber's process of ammonia manufacture:
N
2
(
g
)
+
3
H
2
(
g
)
⟶
2
N
H
3
(
g
)
,
Δ
H
o
25
o
C
=
−
92.2
k
J
Molecules
N
2
(
g
)
H
2
(
g
)
N
H
3
(
g
)
C
P
J
K
−
1
m
o
l
−
1
29.1
28.8
35.1
If
C
P
is independent of temperature,then reaction at
100
o
C
compared to that of
25
o
C
will be:
A
more endothermic
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B
less endothermic
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C
more exothermic
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D
less exothermic
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Solution
The correct option is
D
less exothermic
Suggest Corrections
0
Similar questions
Q.
In Haber's process of manufacturing of ammonia,
N
2
(
g
)
+
3
H
2
(
g
)
→
2
N
H
3
(
g
)
:
H
0
25
∘
C
=
−
92.2
k
J
Molecule
N
2
(
g
)
H
2
(
g
)
N
H
3
(
g
)
C
p
(
J
K
−
1
m
o
l
e
−
1
)
29.1
28.8
35.1
If
C
p
is independent of temperature, then, reaction at
100
∘
C
as compared to that of
25
∘
C
will be:
Q.
In the manufacture of ammonia by Haber's process,
N
2
(
g
)
+
3
H
2
(
g
)
⇋
2
N
H
3
(
g
)
+
92.3
kJ. Which of the following conditions is unfavourable?
Q.
In Haber's process, the ammonia is manufactured according to the following reaction:
N
2
(
g
)
+
3
H
2
(
g
)
⇌
2
N
H
3
(
g
)
;
Δ
H
o
=
−
22.4
k
J
/
m
o
l
The pressure inside the chamber is maintained at
200
atm and temperature at
500
o
C
. Generally, this reaction is carried out in the presence of
F
e
catalyst.
500
o
C
is considered optimum temperature for Haber's process because:
Q.
The enthalpy change for a reaction
N
2
(
g
)
+
3
H
2
(
g
)
→
2
N
H
3
(
g
)
is -92.2 kJ/mol. Calculate the enthalpy of formation of ammonia.
Q.
Use the following data to calculate
Δ
S
0
for the reaction:
2
N
H
3
(
g
)
⟶
N
2
(
g
)
+
3
H
2
(
g
)
Compound
S
o
(J/mol-K)
H
2
(
g
)
N
2
(
g
)
N
H
3
(
g
)
-98.74
-114.99
-304.99
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