In Hall-Heroult process, the product obtained at the anode is:

Aluminium

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Oxygen

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Fluorine

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Alumina

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Solution

The correct option is B Oxygen
In Hall-Heroult’s Process, alumina is dissolved into cryolite, whose melting point is more manageable.
The reactions involved at cathode and anode are as follows:
At Cathode:
$2 A l^{3 +} + 6 e^{-} \to 2 A l$
At Anode:
$2 A l_{2} O_{3} \to 2 A l^{3 +} + 3 O^{2 -}$
$3 O^{2 -} \to 3 / 2 O_{2} + 6 e -$
So, the product obtained at anode is oxygen.

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