Question

In Hardy-Weinberg equation the frequency of heterozygous individuals is represented by :

• A. $q^2$
• B. $p^2$
• C. $2pq$
• D. $pq$

Answer 1

The correct option is C $2pq$

The Hardy-Weinberg equation is given by :

p² + 2pq + q² = 1

Here, p and q represent the individual allele frequencies.

Therefore, p² = frequency of homozygous condition represented by p.

q²= frequency of homozygous alleles represented by q.

and 2pq = frequency of heterozygous condition.

So, the correct answer is '2pq'