In head on collision of two point particles-loss in kinetic energy is given by - K-m1m2-2m1-m2-u-1-u-2-21-k2With usual notation except k- the dimensional formula of quantity k is

The correct option is A [M^0L^0T^0] #10; #10; #10; #10; #10; #10; #10; #10;It is clear that (1 k^2) is dimensionless so [k]=[M ...

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Standard XII

Physics

Velocity of Separation and Approach

In head on co...

Question

In head on collision of two point particles,loss in kinetic energy is given by
$Δ K = \frac{m_{1} m_{2}}{2 (m_{1} + m_{2})} | {\to u}_{1} - {\to u}_{2} |^{2} (1 - k^{2})$
With usual notation (except $k$ ), the dimensional formula of quantity $k$ is

[M^{0} L^{0} T - 1]

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[M^{0} L^{0} T^{0}]

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[M^{0} L T - 1]

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[M^{0} L^{2} T - 2]

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Solution

The correct option is A $[M^{0} L^{0} T^{0}]$

It is clear that $(1 - k^{2})$ is dimensionless so $[k] = [M^{0} L^{0} T^{0}]$

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In head on collision of two point particles,loss in kinetic energy is given by ΔK=m1m22(m1+m2)|→u1−→u2|2(1−k2)With usual notation (except k), the dimensional formula of quantity k is

The correct option is A [M0L0T0] It is clear that (1−k2) is dimensionless so [k]=[M0L0T0]

In head on collision of two point particles,loss in kinetic energy is given by
$Δ K = \frac{m_{1} m_{2}}{2 (m_{1} + m_{2})} | {\to u}_{1} - {\to u}_{2} |^{2} (1 - k^{2})$
With usual notation (except $k$ ), the dimensional formula of quantity $k$ is

The correct option is A $[M^{0} L^{0} T^{0}]$

It is clear that $(1 - k^{2})$ is dimensionless so $[k] = [M^{0} L^{0} T^{0}]$