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Question
In heat transfer,Temperature is analogous to :
In heat transfer,Temperature is analogous to :
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Solution
The correct option is B potential difference
dQdt=KAL x temperature gradient
This can be rewritten as:
Thermal current =temperature gradientLKA
Also by Ohm's law, I=VR
Comparing the above two, we get that temperature gradient is similar to potential difference and LKA is similar to resistance and is called thermal resistance.
dQdt=KAL x temperature gradient
This can be rewritten as:
Thermal current =temperature gradientLKA
Also by Ohm's law, I=VR
Comparing the above two, we get that temperature gradient is similar to potential difference and LKA is similar to resistance and is called thermal resistance.
Thermal current =temperature gradientLKA
Also by Ohm's law, I=VR
Comparing the above two, we get that temperature gradient is similar to potential difference and LKA is similar to resistance and is called thermal resistance.
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