Question

In Heisenberg's uncertainty equation $\Delta \text{x}.\Delta \text{p}\ge \frac{\text{h}}{4\pi }$, $\Delta \text{p}$ stands for_____.

• A. uncertainty in energy
• B. uncertainty in position
• C. uncertainty in momentum
• D. uncertainty in mass

Answer 1

The correct option is C uncertainty in momentum

Heisenberg's uncertainty principle states that it is impossible to determine both the position and the momentum of a an electron inside an atom simultaneously.

Mathematically, it is derived that the product of uncertainties in position and momentum is greater than or equal to a constant $\frac{\text{h}}{4\pi }$. The equation for that is:

$\Delta \text{x}.\Delta \text{p}\ge \frac{\text{h}}{4\pi }$ where,

$\Delta \text{x}$ = Uncertainty in position
$\Delta \text{p}$ = Uncertainty in momentum
$\text{h}$ = Planck's constant