Question

In Hell-Volhard-Zelinsky reaction, the carboxylic acids are halogenated at A position by using B and C. Identify A, B and C.

• A. $\begin{array}{ccc}\text{A}& \text{B}& \text{C}\\ \alpha & NaOH& \text{Iodine}\end{array}$
• B. $\begin{array}{ccc}\text{A}& \text{B}& \text{C}\\ \alpha & \text{Phosphorous}& \text{Halogen}\end{array}$
• C. $\begin{array}{ccc}\text{A}& \text{B}& \text{C}\\ \beta & \text{Phosphorous}& H_{2}O\end{array}$
• D. $\begin{array}{ccc}\text{A}& \text{B}& \text{C}\\ \beta & PC{l}_5& NaOH\end{array}$

Answer 1

The correct option is B $\begin{array}{ccc}\text{A}& \text{B}& \text{C}\\ \alpha & \text{Phosphorous}& \text{Halogen}\end{array}$