In $H N_{3}$ , oxidation number of nitrogen is

- 3

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- 1

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- 0.33

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0.5

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Solution

The correct option is B $- 0.33$
$H N_{3}$ is also known as hydrazoic acid.
Since, it is a neutral compound, sum of oxidation states of all elements is equal to zero.
Therefore, $1 + 3 x = 0$
or, $x = - \frac{1}{3}$
Hence, the oxidation number of $N$ is $- \frac{1}{3} = - 0.33$ .

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