In homogeneous liquid Phase reaction, ethyl acetate is formed by reaction of ethanol and acetic acid and equilibrium is achieved at temperature T(K). Then (1) Kp of this homogeneous liquid Phase reaction will be zero (2) Kc of this homogenous liquid phase reaction is not defined (3) On dilution, Kc will remain same (4) On increase in concentration of ethyl-alcohol, Kc will decrease

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Q. For a homogeneous gaseous reaction,

K_{p} = K_{c}

hence

Δ n_{g}

for the reaction will be:

Ethyl acetate is formed by the reaction between ethanol and acetic acid and the

equilibrium is represented as:

(i) Write the concentration ratio (reaction quotient), Qc, for this reaction (note: water is not in excess and is not a solvent in this reaction)

(ii) At 293 K, if one starts with 1.00 mol of acetic acid and 0.18 mol of ethanol, there is 0.171 mol of ethyl acetate in the final equilibrium mixture. Calculate the equilibrium constant.

(iii) Starting with 0.5 mol of ethanol and 1.0 mol of acetic acid and maintaining it at 293 K, 0.214 mol of ethyl acetate is found after sometime. Has equilibrium been reached?

Ethyl acetate is formed by the reaction between ethanol and acetic acid and the equilibrium is represented as:

(i) Write the concentration ratio (reaction quotient), Qc, for this reaction (note: water is not in excess and is not a solvent in this reaction)

(ii) At 293 K, if one starts with 1.00 mol of acetic acid and 0.18 mol of ethanol, there is 0.171 mol of ethyl acetate in the final equilibrium mixture. Calculate the equilibrium constant.

(iii) Starting with 0.5 mol of ethanol and 1.0 mol of acetic acid and maintaining it at 293 K, 0.214 mol of ethyl acetate is found after sometime. Has equilibrium been reached?

Q. For a homogeneous chemical reaction,