Question

In how many different ways can 3 boys and 4 girls be arranged in a row such that all boys stand together and all the girls stand together?

• A. 288
• B. 144
• C. 72
• D. 36

Answer 1

The correct option is A 288

Total no. of ways in which girls can stand in the queue = 3! Similarly, for boys = 4! Either boys or girls group can be in the front. So, there are two possible set of arrangements. Hence, the total no. of ways possible $=3!\times 4!\times 2=288$