Question

In how many different ways can the letters of the word ' KURUKSHETRA' be arranged?

Answer 1

Number of letters in the word 'KURUKSHETRA' is $11$ of which $2$ are $K$'s, $2$ are $U$'s, $2$ are $R$'s and remaining are different.
Thus required number of permutations
$=\frac{11!}{2!2!2!}$
$=4989600$