In how many elements does the last electron have the quantum numbers of $n = 4$ and $l = 1$ ?

4

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6

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8

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10

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Solution

The correct option is C $6$
$l = 1$ for p subshell and $n = 4$
$⟹ 4 p$
It can accomodate 6 electrons. So a total of 6 different elements can have the last electron with quantum numbers $n = 4$ and $l = 1$

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Similar questions

n = 4, l = 0, m = \pm 1

(i) n = 4, m_{s} = - \frac{1}{2}

(i i) n = 3, l = 0

(i i i) n = 2, l = 1

(i v) n = 2, l = 0

n = 4, m_{s} = - 1 / 2

n = 3, l = 0

How many electrons in an atom may have the following quantum numbers?
(a) n = 4, $m = - \frac{1}{2}$
(b) n = 3, l = 0

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