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Question

In how many of the distinct permutations of the letters in “MISSISSIPPI” do the four I’s not come together?


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Solution

Step 1: Calculate the total number of permutations

The given word is “MISSISSIPPI”.

Here, the number of M is 1, I is 4, S is 4 and P is 2.

So, the total number of letters =1+4+4+2

the total number of letters =11

Thus, the total number of ways to arrange all the letters can be calculated as follows,

The total number of ways to arrange 11 letters =11!1!×4!×4!×2!

The total number of ways to arrange 11 letters =11×10×9×8×7×6×5×4!1×4!×4×3×2×1×2×1

The total number of ways to arrange 11 letters =34650

Step 2: Calculate the number of permutations when I's comes together

Now, let us say that the 4I's come together. And, then assume these 4I's to be a single letter.

Then, the number of available letters =11-4+1

the number of available letters =8

Thus, the number of ways to arrange these 8 letters can be calculated as follows,

The total number of ways to arrange 8 letters =8!1!×1!×4!×2!

The total number of ways to arrange 8 letters =8×7×6×5×4!1×1×4!×2×1

The total number of ways to arrange 8 letters =840

Step 3: Calculate the required number of permutations

Now, the number of distinct permutations of the letters in “MISSISSIPPI” where the four I’s not come together can be calculated as,

The number of required permutations = total number of ways to arrange 11 letters - total number of ways to arrange 8 letters

The number of required permutations =34650-840

The number of required permutations =33810

Hence, in 33810 distinct permutations of the letters in “MISSISSIPPI” the four I’s not come together.


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