In how many seconds should a charge of 10 C flow between two terminals so as to maintain a constant current of 100 A?

1/10 s

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10 s

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110 s

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1/110 s

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Solution

The correct option is A
1/10 s

We know that, rate of flow of charge is called current.

I = $\frac{q}{t}$

So t = $\frac{q}{I}$ = $\frac{10}{100}$ = $\frac{1}{10}$ s

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In how many seconds should a charge of 10 C flow between two terminals so as to maintain a constant current of 100 A?

The correct option is A 1/10 s We know that, rate of flow of charge is called current. I = qt So t = qI = 10100 = 110 s

The correct option is A
1/10 s

We know that, rate of flow of charge is called current.

I = $\frac{q}{t}$

So t = $\frac{q}{I}$ = $\frac{10}{100}$ = $\frac{1}{10}$ s