In how many ways $4$ married couples can be seated round a table if no husband and wife as well as no two men are to be in adjacent seats.

384

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

14

No worries! We‘ve got your back. Try BYJU‘S free classes today!

24

No worries! We‘ve got your back. Try BYJU‘S free classes today!

36

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $384$
$4$ married couples
$\Rightarrow 4$ Men , $4$ women
Therefore then men can be arranged in $4!$ ways
and there are $4$ places with every place having two ways
$= 24 \times 2 \times 2 \times 2 \times 2 = 24 \times 4 \times 4 = 24 \times 16 = 384$

Suggest Corrections

Similar questions

Q. In how many ways can

8

persons consisting of

4

men and

4

women can be seated round a table if no two men are to be in adjacent seats.

Q. In how many ways can

4

married couples seat themselves around circular table if there are no restrictions?

In how many ways can a party of 4 men and 4 women be seated at a circular table so that no two women are adjacent?

In how many ways $n$ married couples can be arranged around a table so that men and women are alternate and each woman is not adjacent to her husband?

Q. In how many ways can n men be seated around a round table when in no two ways a man has the same neighbours?

Join BYJU'S Learning Program

In how many ways 4 married couples can be seated round a table if no husband and wife as well as no two men are to be in adjacent seats.

The correct option is B 3844 married couples⇒4 Men , 4 women Therefore then men can be arranged in 4! ways and there are 4 places with every place having two ways =24×2×2×2×2=24×4×4=24×16=384

In how many ways $4$ married couples can be seated round a table if no husband and wife as well as no two men are to be in adjacent seats.

The correct option is B $384$
$4$ married couples
$\Rightarrow 4$ Men , $4$ women
Therefore then men can be arranged in $4!$ ways
and there are $4$ places with every place having two ways
$= 24 \times 2 \times 2 \times 2 \times 2 = 24 \times 4 \times 4 = 24 \times 16 = 384$