Question

In how many ways $5$ girls and $5$ boys can be seated in row such that they sit alternatively

• A. $2\times 5{!}^2$
• B. $10!$
• C. $5{!}^2$
• D. none of these

Answer 1

The correct option is A $2\times 5{!}^2$

G_ G_ G_G_ G_

_ G_ G_ G_ G_G

$5$ boys can be permuted in $5!$ ways

Now for making seating arrangement $5$ girls alternatively to $5$ boys.

$5$ girls can be permuted in $5!$ ways.

Total number$=2\times 5!\times 5!$