Question

In how many ways a committee of $5$ members to be formed out of $6$ boys and $4$ girls, if:
two girls are included in the committee

Answer 1

Given that , $2$ girls are in committee

P(selecting $2$ girls)$=C_2^4=\frac{4!}{2!.2!}=6$

P(selecting $3$ boys)$=C_3^6=\frac{6!}{3!.3!}=\frac{6\times 5\times 4}{6}=20$

No. of ways$=6\times 20=120$