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Question
In how many ways, a party of 5 men and 5 women be seated at a circular table, so that no two women are adjacent?
In how many ways, a party of 5 men and 5 women be seated at a circular table, so that no two women are adjacent?
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Solution
The correct option is D 2880
The 4 men can be seated at a circular table such that there is a vacant seat between every pair of men in (5 – 1)! = 4! = 24 ways. Now, 5 vacant seats can be occupied by 5 women in 5! = 120 ways.
Hence, the required number of seating arrangements = 24 x 120 = 2880
2880
The 4 men can be seated at a circular table such that there is a vacant seat between every pair of men in (5 – 1)! = 4! = 24 ways. Now, 5 vacant seats can be occupied by 5 women in 5! = 120 ways.
Hence, the required number of seating arrangements = 24 x 120 = 2880
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