The correct option is D 6
If a team includes N, it cannot include L. And therefore not even 'K' (from statement five and three) According to statement one One of P (or) R (or) S has to be included.
According to statement two
One of M (or) Q has to be selected.
So the following cases are possible
P N Q,
R Q N,
P M N,
R M N,
If 'S' is selected
SUWMN,
SUWQN,
are the only possible cases.
Hence in all 4 + 2 = 6 ways can be constituted.