In how many ways a team of 11 be chosen from 20 students of a class so that 2 particular students are alwayts included and 5 are always excluded?

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Solution

Remaining students $= 20 - 2 - 5$
$= 13$
Out of them we have to select $9$ more players
$\Rightarrow^{13} C_{9}$ ways $= \frac{13.12.11.10}{4.3.2} = \frac{1430}{2}$
$= 715$
$\Rightarrow (A)$ .

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In how many ways a team of 11 be chosen from 20 students of a class so that 2 particular students are alwayts included and 5 are always excluded?

Remaining students=20−2−5=13Out of them we have to select 9 more players⇒13C9 ways =13.12.11.104.3.2=14302=715⇒(A).

Remaining students $= 20 - 2 - 5$
$= 13$
Out of them we have to select $9$ more players
$\Rightarrow^{13} C_{9}$ ways $= \frac{13.12.11.10}{4.3.2} = \frac{1430}{2}$
$= 715$
$\Rightarrow (A)$ .