Question

In how many ways can 10 sprinters be arranged in a race so that 3 rank-holders are always together?

• A. $9!\times 3!$
• B. $8!\times 3!$
• C. $10!\times 3!$
• D. $13!\times 3!$

Answer 1

The correct option is B $8!\times 3!$

We can thought 3 range holders as a

1 group there total sprinters is $7+1=8$

$\therefore$ no of ways $=8!$

Also '3' range holders can change there

position $\Rightarrow$ total ways $=8!\times 3!$