In how many ways can $20$ different colored beads can be strung on a necklace?

\frac{19!}{2}

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20!

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19!

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18!

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Solution

The correct option is D $\frac{19!}{2}$
With the given $20$ different colored beads ,according to circular permutation
Number of ways $= \frac{(20 - 1)!}{2} = \frac{19!}{2}$

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