Question

In how many ways can $2744$ be resolved as a product of two factors?

• A. $16$
• B. $14$
• C. $6$
• D. $8$

Answer 1

The correct option is D $8$

If the prime factorisation of a number $N=a^m\times b^n......$ then number of factors is $(m+1)\times (n+1)....$ and so on
So, Prime factorisation of $2744=2^3\times 7^4$
And number of factors it has $=(3+1)\times (3+1)=4\times 4=16$
And number of ways it can be resolved a product of two factors $=\frac{16}{2}=8$