The correct option is D 120
The letter boxes can be selected in 6C3 ways =(6×5×4)(1×2×3)=20
The letters can be arranged among these boxes in 3! ways = 6
Hence, The total no. of possibilities =20×6=120
Special Case : If there were no restrictions (ie. If any no. of letters can be posted in each box)
The first letter can be posted in 6 boxes.
Second and third letters can also posted in 6 ways each.
Hence, the total no. of possibilities = 6×6×6
= 216