Question

In how many ways can 3 prizes be distributed among 4 boys, when
(i) no boy gets more than one prize?
(ii) a boy may get member of prizes?
(iii) no boy gets all the prizes?

Answer 1

total no. of boys $=4$
No. of prizes $=3$
total no. of ways $=y^3$
No. of ways when pne boy will get three prizes $=4cl\times 1=4$
$\therefore$ favourable $prize=y^3-y$