In how many ways can 5 green toys and 5 red toys be arranged, such that 2 particular red toys are never together whereas 2 particular green toys are always together?

7*8!*2!

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7*8!

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7*7!*2!

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9! - 8!

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Solution

The correct option is A
78!2!

The number of arrangements in which two particular red toys are never together and two particular green toys are always together is = 9!2! – 8!2!2! = 78!2!

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In how many ways can 5 green toys and 5 red toys be arranged, such that 2 particular red toys are never together whereas 2 particular green toys are always together?

The correct option is A 7*8!*2! The number of arrangements in which two particular red toys are never together and two particular green toys are always together is = 9!2! – 8!2!2! = 7*8!*2!

The correct option is A
78!2!

The number of arrangements in which two particular red toys are never together and two particular green toys are always together is = 9!2! – 8!2!2! = 78!2!