The correct option is
C 3600
The no. of circular arrangements of n distinct items = (n-1)!
If A,B,C,D,E,F,G and H are the 8 persons to be seated around the table and A,B the 2
particular persons who must not sit together. Then,
![](https://search-static.byjusweb.com/question-images/byjus/Lq3i0b8ym9aUFU7Tt7oDmDP0OhTdGcvgn92wXPpFe1EybiUCcUTtBbuXUFqcnKiYzIq_SLZ_nTQuBTS9KDRT3FOIf9Oq7zDhNsi5aeq08LQD3kEsE_wjJ2o7is7Hz8VXfcj9vb4)
The total no. of circular arrangements for 8 persons = (8-1)! = 7! = 5040 ---> (1)
The no. of circular arrangements possible if A and B were to sit together = 6! (considering A and B as a single pair).
But, A and B can interchange their positions.
Hence, the no. of arrangements
=6!×2=720×2=1440−−−−>(2) So, the total number of arrangements possible if A and B must not sit together, = (1) - (2)
= 5040-1440
= 3600