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Question

In how many ways can 8 persons be seated at a round table if 2 particular persons must not sit next to each other?

A
40320
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B
5040
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C
3600
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D
720
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Solution

The correct option is C 3600
The no. of circular arrangements of n distinct items = (n-1)!
If A,B,C,D,E,F,G and H are the 8 persons to be seated around the table and A,B the 2
particular persons who must not sit together. Then,

The total no. of circular arrangements for 8 persons = (8-1)! = 7! = 5040 ---> (1)
The no. of circular arrangements possible if A and B were to sit together = 6! (considering A and B as a single pair).
But, A and B can interchange their positions.
Hence, the no. of arrangements =6!×2=720×2=1440>(2)
So, the total number of arrangements possible if A and B must not sit together, = (1) - (2)
= 5040-1440
= 3600

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