In how many ways can 80 be written as the difference of squares of two natural numbers?
3
This is because if we are writing a number N as a difference of squares, then -
N=a2−b2⟹N=(a+b)(a−b). If (a+b, a-b) is a pair of one odd and one even number, 'a' and 'b' can't be natural numbers.
Hence, both the factors need to be either even or odd.
In the case of 80, the possible cases are 80=2×40; =4×20;=8×10.
Thus, there are only three instances where both are even. Hence, the answer is option (b).