Question

In how many ways can a committee of five be formed from amongst four boys and six girls so as to include exactly two girls?

• A. $35$
• B. $25$
• C. $55$
• D. $60$

Answer 1

The correct option is D $60$

Committee of $:5$

$4$ Boys , $6$ Girls

Include exactly $2$ women Included number of ways :

${}^6{C}_2{\times }^4{C}_3=\frac{6\times 5}{2}\times \frac{4}{3!}=60$

Therefore number of ways of selection $=60$