Question

In how many ways can a cricket-eleven is chosen out of $16$ players such that a particular player is always chosen

• A. $3003$
• B. $1400$
• C. $1583$
• D. $1632$

Answer 1

The correct option is A $3003$

$11$ Cricketers ti be selected of $16$ players

$1$ is always choosen

$\Rightarrow 10$ shouls be selected of $15$ players

${\Rightarrow }^{15}{C}_{10}=\frac{15\times 14\times 13\times 12\times 11}{5\times 4\times 3\times 2\times 1}=77\times 39=3003$