Question

In how many ways can four people, each throwing a dice once, make a sum of $6$?

• A. ${}^9{C}_2$
• B. ${}^{10}{C}_3$
• C. ${}^8{C}_3$
• D. ${}^9{C}_3$

Answer 1

The correct option is A ${}^9{C}_2$

Required number of ways is ${=}^9{C}_2$

Hence, correct option is (A)