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Question

In how many ways can one choose 4 cards from a normal deck of cards so as to have all suits present?


A

(134) x 48 x 47

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B

(134) x 27 x 47

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C

48C6

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D

134

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E

(134) x 48C6

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Solution

The correct option is D

134


52 cards in a deck -13 cards per suit

First card - let us say from suit hearts = 13C1 =13

Second card - let us say from suit diamonds = 13C1 =13

Third card - let us say from suit spade = 13C1 =13

Fourth card - let us say from suit clubs = 13C1 =13

Total number of ways = 13 * 13 * 13 * 13 = 134


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