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Question

In how many ways can one select a cricket team of eleven from 17 players in which only 5 players can bowl if each cricket team of 11 must include exactly 4 bowlers?

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Solution

It is given that out of 17 players, 5 players are bowlers. 4 bowlers are selected in the way that the combination of 5 players taken 4 at a time.

The formula for the combination is defined as,

C n r = n! ( nr )!r! .

Substitute 5 for n and 4 for r in the above formula.

C 5 4 = 5! ( 54 )!4! = 5! 1!4!

Cancel the common factors by factorizing the bigger term to the factorial.

The formula to calculate the factors of a factorial in terms of factorial itself is,

n!=n( n1 )! n!=n( n1 )( n2 )![ n2 ]

The combination is written as,

C 5 4 = 5×4! 4! =5

The number of ways that the bowlers are selected is 5.

Now, since 17 players contains 5 bowlers, thus the players left are 12 and similarly, the team of 11 players contain 4 bowlers, thus the players remained are 7.

So, the remaining players are calculated as the combination of 12 players taken 7 at a time.

The formula for the combination is defined as,

C n r = n! ( nr )!r!

Substitute 12 for n and 7 for r in the above formula.

C 12 7 = 12! ( 127 )!7! = 12! 5!7!

Cancel the common factors by factorizing the bigger term to the factorial.

The formula to calculate the factors of a factorial in terms of factorial itself is,

n!=n( n1 )! n!=n( n1 )( n2 )![ n2 ]

The combination can be written as,

C 12 7 = 12×11×10×9×8×7! 7!5×4×3×2×1 = 12×11×10×9×8 5×4×3×2×1 =792

Thus, the number of ways that the remaining players are selected is 792.

By multiplication principle which states that if an event can occur in m different ways and follows another event that can occur in n different ways, the total number of ways is m×n.

The number of ways that the cricket team is selected is,

792×5=3960

Thus, the cricket team can be selected in 3960 ways.


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