Question

In how many ways can six ${}^{\prime }{+}^{\prime }$ and four ${}^{\prime }{-}^{\prime }$ symbols can be placed in a row if no two ${}^{\prime }{-}^{\prime }$ signs are together?

Answer 1

For two ${}^{\prime }{-}^{\prime }$ sign are not together,

the number of possible ways is

$=6!(\frac{7}{4})4!$