Question

In how many ways can the number 286 be written as a sum of two or more consecutive integers?

• A. 3
• B. 1
• C. 2
• D. 4

Answer 1

The correct option is A

3

Shortcut - Number of ways in which a no. N can be written as a sum of two or more consecutive integers = (No. of odd factors of that number-1)
$286=2\times 11\times 13$. So, it has 4 odd factors - 1, 11, 13, 143.

(No. of odd factors - 1) = 4 - 1 = 3.