Question

In how many ways can we distribute $5$ different balls in $4$ different boxes when order is not consider inside the boxes and empty boxes are not allowed

• A. $120$
• B. $150$
• C. $240$
• D. $Noneofthese$

Answer 1

The correct option is A $120$

$4$ ball can be selected from $5$ balls in ${}^5{C}_4$ ways which can be arranged by $4!$ ways in $4$ boxes.

So, Total no. of ways

${=}^5{C}_4\times 4!=120$

Hence,

Option $A$ is correct answer.