In how many ways can we select three natural numbers out of the first $10$ natural numbers so that they are in geometrical progression with the common ratio greater than $1$ ?

2

ways

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3

ways

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4

ways

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5

ways

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6

ways

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Solution

The correct option is B $3$ ways
$1, 2, 4$ is GP with first term 1 and common ratio $2 (> 1) .$
$1, 3, 9$ is GP with first term 1 and common ratio $3 (> 1) .$
$2, 4, 8$ is GP with first term 2 and common ratio $2 (> 1) .$
Only $3$ ways.
Option B is correct.

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In how many ways can we select three natural numbers out of the first 10 natural numbers so that they are in geometrical progression with the common ratio greater than 1?

The correct option is B 3 ways1,2,4 is GP with first term 1 and common ratio 2(>1).1,3,9 is GP with first term 1 and common ratio 3(>1).2,4,8 is GP with first term 2 and common ratio 2(>1).Only 3 ways.Option B is correct.

In how many ways can we select three natural numbers out of the first $10$ natural numbers so that they are in geometrical progression with the common ratio greater than $1$ ?

The correct option is B $3$ ways
$1, 2, 4$ is GP with first term 1 and common ratio $2 (> 1) .$
$1, 3, 9$ is GP with first term 1 and common ratio $3 (> 1) .$
$2, 4, 8$ is GP with first term 2 and common ratio $2 (> 1) .$
Only $3$ ways.
Option B is correct.