Question

In how many ways four $+$ and five $-$ sign can be arranged in a circle so that no two $+$ sign are together?

• A. $4!.5!$
• B. $2$
• C. $4!.4!$
• D. $1$

Answer 1

The correct option is D $1$

First we arrange $(-)$ sign $\because$ all of them are identical $\therefore$ there is only $1$ way,

In any way we arrange it will be similar.

Hence, the answer is $1.$