Case 1: If all three women always sit together
We can club the 3 women in one group and the number of arrangements of this group will be 3!
Now, 4 men and 1 group of women can be arranged arround a round table =(5−1)!
Hence, Total arrangements =4!3!=144.
Now, case 2: If all three women never sit together
Total arrangements without any constraints =6!
From case 1, we know the arrangements if women always sit together.
Hence, Total arrangements =6!−144=720−144=576=6!−4!3!=576