Question

In how many ways it is possible to divide six identical green, six identical blue and six identical red among two persons such that each gets equal number of item?

Answer 1

There are total $18$ balls.

These balls should be distributed equally among two persons so these are as

many number of ways as in which we can did divide these balls in two equal

groups of $9-9$ Balls.

So, $\frac{18!}{9!9!2!}$

($2!$ because two groups have same size)