Question

In how many ways it is possible to divide six identical green, six identical blue and six identical red balls, among two persons such that each gets the equal number of the item?

• A. $37530$
• B. $7423$
• C. $24310$
• D. $1538$

Answer 1

The correct option is C $24310$

There are total $18$ balls.

The ball should be distributed equally so each will get $9$ balls

So our answer will be $\frac{18!}{9!\times 9!}\times \frac{1}{2!}=24310$

$\frac{1}{2!}$ is because both groups have same numbers that is $9$