In how much time (in seconds) should a charge of 10 C flow between the two terminals so as to maintain a constant current of 100 A?

1/10 s

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10 s

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110 s

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1/110 s

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Solution

The correct option is A
1/10 s

Current is the rate of flow of charge.

i.e., I = $\frac{q}{t}$

So time, t = $\frac{q}{I}$ = $\frac{10}{100}$ = $\frac{1}{10}$ s

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In how much time (in seconds) should a charge of 10 C flow between the two terminals so as to maintain a constant current of 100 A?

The correct option is A 1/10 s Current is the rate of flow of charge. i.e., I = qt So time, t = qI = 10100 = 110 s

The correct option is A
1/10 s

Current is the rate of flow of charge.

i.e., I = $\frac{q}{t}$

So time, t = $\frac{q}{I}$ = $\frac{10}{100}$ = $\frac{1}{10}$ s