In how much time (in seconds) should a charge of $10 C$ flow between the two terminals so as to maintain a constant current of $100 A$ ?

110 s e c o n d s

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10 s e c o n d s

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\frac{1}{110} s e c o n d s

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\frac{1}{10} s e c o n d s

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Solution

The correct option is D $\frac{1}{10} s e c o n d s$
Current $(I)$ is the rate of flow of charge $(q)$ through a cross section per unit time $(t)$ .
$I = \frac{q}{t}$
Given: $q = 10 C$ , $I = 100 A$
$t = \frac{q}{I}$
$t = \frac{10 C}{100 A}$
$t = \frac{1}{10} s$

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In how much time (in seconds) should a charge of 10 C flow between the two terminals so as to maintain a constant current of 100 A?

The correct option is D 110 secondsCurrent (I) is the rate of flow of charge (q) through a cross section per unit time (t). I=qt Given: q=10 C, I=100 A t=qI t=10 C100 A t=110 s

In how much time (in seconds) should a charge of $10 C$ flow between the two terminals so as to maintain a constant current of $100 A$ ?

The correct option is D $\frac{1}{10} s e c o n d s$
Current $(I)$ is the rate of flow of charge $(q)$ through a cross section per unit time $(t)$ .
$I = \frac{q}{t}$
Given: $q = 10 C$ , $I = 100 A$
$t = \frac{q}{I}$
$t = \frac{10 C}{100 A}$
$t = \frac{1}{10} s$